3x^2-80x+220=0

Solution for 3x^2-80x+220=0 equation:

3x^2-80x+220=0

a = 3; b = -80; c = +220;
Δ = b2-4ac
Δ = -802-4·3·220
Δ = 3760
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3760}=\sqrt{16*235}=\sqrt{16}*\sqrt{235}=4\sqrt{235}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-4\sqrt{235}}{2*3}=\frac{80-4\sqrt{235}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+4\sqrt{235}}{2*3}=\frac{80+4\sqrt{235}}{6}
$